Calculating the size of an Arial regular text design

Hello everyone,

I’m trying to figure out how to calculate the size of an artistic text, i.e. without including the top and bottom margins.
artistic-text.png
Here are the contextual elements:
—I’m working on a document in 400 DPI, in CMYK mode, using DTP software or vector drawing software (Affinity Suite).
—I’m using the Arial Regular font to write the text ‘ELEPHANT’.
—After selecting all the text, I reduce the height proportionally to 0.087 inches.
—The software gives me a font size of 8.750799 pt.

I’d like to know how this result can be explained by calculation using the typographic properties of the Arial font. Here are the properties I have in Hight-Logic FontCreator:

—Typo ascender: 1491
—Typo descender: -431
—Typo line gap: 307
—Win Ascent: 1854
—Ascender: 1854
—Descender: -434
—Line gap: 67
—Cap height: 1467
—x-height: 1062
—Vertical typo ascender: 1024
—Vertical typo descender: -1024
—Subscript horizontal font size: 1434
—Subscript vertical font size: 1331

How do these properties translate in terms of calculation to obtain the final size of 8.750799 pt?

Thank you in advance for your clarification and help!

The FAQ may help.

I’ve already seen this information, but there’s something I don’t understand, as I can’t find by calculation the value of 8.750799 pt obtained by manipulation with the font.
Hence the question about the Arial font that everyone has.

To me it seems a document in 100 DPI, as 8.750799 / 100 = 0.087.

Can you do some more testing with another font?

I asked this question on the Affinity forum.

I thought that glyph sizes for fonts like Arial were uniform, but I was wrong.

I was looking for a formula to automatically determine the correct font size for text on the spine of a book. However, it turns out that the size of a word depends on the size of each of its glyphs, which makes it impossible to calculate the size of a word in a general way.

For those interested, the solution is to write the word in artistic text without distortion, then reduce it proportionally to the desired size, in this case 0.087 inches.